Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 982 893 1024 995 982 893 1024 995 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 0.12, 0.15, 0.2 and 0.54? 2.8 9.2 5.4 7.8 2.8 9.2 5.4 7.8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Make the number of decimal places in all the given numbers the same i.e., 0.12, 0.15, 0.2 and 0.54LCM of 12, 15, 20 and 542|12 15 20 542|6 15 10 273|3 15 5 275|1 5 5 9 1 1 1 9LCM=22×3×5×9=540 LCM=540/10 =5.4
Problems on H.C.F and L.C.M The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is : 3363 1677 2523 1683 3363 1677 2523 1683 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the lowest common multiple of 24, 36 and 40. 240 360 480 120 240 360 480 120 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 63 58 27 42 63 58 27 42 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 23 24 21 22 23 24 21 22 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
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