Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 1024 982 893 995 1024 982 893 995 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1008 1032 1015 1022 1008 1032 1015 1022 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 195, 143 395, 343 95, 43 295, 243 195, 143 395, 343 95, 43 295, 243 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 12 and their difference is 12. The numbers are: 66, 78 94, 106 70, 82 84, 96 66, 78 94, 106 70, 82 84, 96 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the H.C.F of 12, 16, 18 and 24? 2 4 3 1 2 4 3 1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 7:25:14 hrs 10:13:17 hrs 9:22:08 hrs 8:27:12 hrs 7:25:14 hrs 10:13:17 hrs 9:22:08 hrs 8:27:12 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
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