Problems on H.C.F and L.C.M L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is : 2 -2 1 -1 2 -2 1 -1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainder respectively, is : 15120 11115 15110 15210 15120 11115 15110 15210 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 505 404 707 606 505 404 707 606 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number? 7 13 11 5 7 13 11 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is: 3600 6400 1600 14400 3600 6400 1600 14400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 432 268 1015 689 432 268 1015 689 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
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