Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 4 13 9 7 4 13 9 7 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 216 548 443 389 216 548 443 389 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 128 127 126 125 128 127 126 125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M. 2574 2474 2774 2674 2574 2474 2774 2674 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574
Problems on H.C.F and L.C.M Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together? None 5 min 5.5 min 5.2 min None 5 min 5.5 min 5.2 min ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1449 1439 1440 1459 1449 1439 1440 1459 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS