Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 7 4 9 13 7 4 9 13 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10020 10010 10015 10080 10020 10010 10015 10080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is: 45 cm 25 cm 55 cm 35 cm 45 cm 25 cm 55 cm 35 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 10 11/10 10/7 10/11 10 11/10 10/7 10/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 48 18 36 24 48 18 36 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 46 minutes and 12 seconds 42 minutes and 36 seconds 45 minutes 26 minutes and 18 seconds 46 minutes and 12 seconds 42 minutes and 36 seconds 45 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
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