Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 7 4 9 13 7 4 9 13 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: 777 1745 364 1045 777 1745 364 1045 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10010 10080 10020 10015 10010 10080 10020 10015 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
Problems on H.C.F and L.C.M Find the highest common factor of 36 and 84. 22 34 12 16 22 34 12 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 36 = 2² x 3²84 = 2² x 3 x 7H.C.F. = 2² x 3 = 12.
Problems on H.C.F and L.C.M A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of th 36 12 50 24 36 12 50 24 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 360 110 180 420 360 110 180 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
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