Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 13 4 9 7 13 4 9 7 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 185 107 111 101 185 107 111 101 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M Find he smallest number of five digits exactly divisible by 16, 24, 36 and 54 . 10688 9368 10368 9868 10688 9368 10368 9868 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18002 17004 18000 18004 18002 17004 18000 18004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 129 131 133 127 129 131 133 127 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 4320 869 427 859 4320 869 427 859 ANSWER DOWNLOAD EXAMIANS APP
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