Problems on H.C.F and L.C.M Express 1168/1095 in simple form? 18/17 17/16 16/15 19/18 18/17 17/16 16/15 19/18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To express any fraction in simple (small form), we have to find the HCF of numerator and denominator. 1095)1168(1 1095 73)1095(15 1095 ——— 0 HCF of 1095 and 1168 is 73Therefore (1168/73)/(1095/73) = 16/15
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 707 606 404 505 707 606 404 505 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16,20, and 24, is : 6400 1600 3600 11400 6400 1600 3600 11400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point. 46 minutes 12 seconds. 26 minutes 18 seconds 45 minutes 42 minutes 36 seconds 46 minutes 12 seconds. 26 minutes 18 seconds 45 minutes 42 minutes 36 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is : 4320 859 427 869 4320 859 427 869 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1439 1449 1440 1459 1439 1449 1440 1459 ANSWER DOWNLOAD EXAMIANS APP
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