Problems on H.C.F and L.C.M Express 1168/1095 in simple form? 18/17 17/16 19/18 16/15 18/17 17/16 19/18 16/15 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To express any fraction in simple (small form), we have to find the HCF of numerator and denominator. 1095)1168(1 1095 73)1095(15 1095 ——— 0 HCF of 1095 and 1168 is 73Therefore (1168/73)/(1095/73) = 16/15
Problems on H.C.F and L.C.M H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is 540 360 180 1260 540 360 180 1260 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: 1 Cannot be calculated equal to their H. F 117 1 Cannot be calculated equal to their H. F 117 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 23 22 21 24 23 22 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 21 25 23 27 21 25 23 27 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 360 1260 180 540 360 1260 180 540 ANSWER DOWNLOAD EXAMIANS APP
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