Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 99 100 97 98 99 100 97 98 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 7 minutes 6 minutes 8 minutes 5 minutes 7 minutes 6 minutes 8 minutes 5 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
Problems on H.C.F and L.C.M Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively. 3013 3036 3024 3002 3013 3036 3024 3002 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 40 32 28 64 40 32 28 64 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 112 116 121 123 112 116 121 123 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 131 127 129 133 131 127 129 133 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
EXAMIANS