Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 66 55 88 77 66 55 88 77 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 869 859 427 4320 869 859 427 4320 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 5 minutes 6 minutes 8 minutes 7 minutes 5 minutes 6 minutes 8 minutes 7 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
Problems on H.C.F and L.C.M Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case. 48 52 22 35 48 52 22 35 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62) = H.C.F. of 70, 105 and 175 = 35.
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12,15,18 and 27. 7720 9720 6720 8720 7720 9720 6720 8720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . Required number = (9999-279) = 9720.
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 127 133 131 129 127 133 131 129 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
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