Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 221 260 143 169 221 260 143 169 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is: 3600 14400 1600 6400 3600 14400 1600 6400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 110 180 360 420 110 180 360 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 601/55 120/11 55/601 11/120 601/55 120/11 55/601 11/120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is : 869 427 859 4320 869 427 859 4320 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? 4 15 16 10 4 15 16 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2
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