Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 221 169 143 260 221 169 143 260 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 45 times their H.C.F. If one of the numbers is 125 and the sum of H.C.F. and L.C.M. is 1150, the other number is: 215 225 220 235 215 225 220 235 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 11720 9720 8720 10720 11720 9720 8720 10720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 11/120 601/55 55/601 120/11 11/120 601/55 55/601 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F of 2923 and 3239 is : 79 47 37 73 79 47 37 73 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 185 107 101 111 185 107 101 111 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
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