Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 5, 10, 15 10, 20, 30 12, 24, 36 4, 8, 12 5, 10, 15 10, 20, 30 12, 24, 36 4, 8, 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number of four digits which is divisible by 15, 24, 40 and 75 is : 9400 9000 9600 9800 9400 9000 9600 9800 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 127 445 379 221 127 445 379 221 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 95, 43 195, 143 295, 243 395, 343 95, 43 195, 143 295, 243 395, 343 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Problems on H.C.F and L.C.M The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is: 48 16 24 12 48 16 24 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 17 18 19 16 17 18 19 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
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