Problems on H.C.F and L.C.M The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of t 2 min 1 min None 3 min 2 min 1 min None 3 min ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M. 2674 2574 2774 2474 2674 2574 2774 2474 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 21 24 31 17 21 24 31 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M The H.C.F of two numbers is 8. Which of the following can never be their L.C.M? 56 24 48 60 56 24 48 60 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of two numbers is 42 and the other two factors of their LCM are 11 and 12. What is the largest number. 504 450 480 462 504 450 480 462 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 707 505 606 404 707 505 606 404 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
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