Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 23 24 22 21 23 24 22 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 0, 62,98 and 130 as remainders respectively is . 15110 11115 15210 15120 15110 11115 15210 15120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together? 5 min None 5.2 min 5.5 min 5 min None 5.2 min 5.5 min ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 31 24 21 17 31 24 21 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1008 1032 1022 1015 1008 1032 1022 1015 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 172, 205 and 304 so as to leave the same remainder in each case? 99 33 None of these 66 99 33 None of these 66 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The greatest number that will divide 172,205 and 304 leaving the same remainder in each case is HCF ((205-172), (304-205), (304-172)) = HCF of 33, 99, and 132 33=31x11 99=3 x 3 x 11 132=3 x 2 x 2 x11 Required number =3 x 11=33
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