Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 24 21 23 22 24 21 23 22 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is: 50/294 60/147 30/7 30/98 50/294 60/147 30/7 30/98 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1080 1075 1095 1085 1080 1075 1095 1085 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which is such that when 697, 909 and 1227 are divided by it, the remainders are all the same? 108 53 112 106 108 53 112 106 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 24 21 17 31 24 21 17 31 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 123 112 121 116 123 112 121 116 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
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