Problems on H.C.F and L.C.M The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: 364 1045 1745 777 364 1045 1745 777 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Problems on H.C.F and L.C.M Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case? 18 17 16 19 18 17 16 19 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of 0.54, 1.8 and 7.2 is: 18 0.018 0.18 1.8 18 0.018 0.18 1.8 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is : 8739 9831 9834 9893 8739 9831 9834 9893 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 4 6 5 3 4 6 5 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 24 21 22 23 24 21 22 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
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