Problems on H.C.F and L.C.M The product of two numbers is 2025 and their HCF is 15 their LCM is: 135 2040 150 2010 135 2040 150 2010 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively? 260 143 221 169 260 143 221 169 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1439 1459 1440 1449 1439 1459 1440 1449 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 221 379 127 445 221 379 127 445 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 30 10 20 40 30 10 20 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: Cannot be calculated F 117 equal to their H. 1 Cannot be calculated F 117 equal to their H. 1 ANSWER DOWNLOAD EXAMIANS APP
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