Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: -2 1 -1 2 -2 1 -1 2 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 869 4320 427 859 869 4320 427 859 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work? 35 40 39 37 35 40 39 37 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 9 : 31 am 10 : 31 am 11 : 31 am 12 : 31 am 9 : 31 am 10 : 31 am 11 : 31 am 12 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Problems on H.C.F and L.C.M LCM of 87 and 145 is: 1305 48 875 435 1305 48 875 435 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 133 127 129 131 133 127 129 131 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
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