Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: -2 2 1 -1 -2 2 1 -1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is 1015 1032 1008 1022 1015 1032 1008 1022 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10010 10015 10020 10080 10010 10015 10020 10080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 243 seconds 242 seconds 240 seconds 246 seconds 243 seconds 242 seconds 240 seconds 246 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 893 1024 995 982 893 1024 995 982 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 9:22:08 hrs 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs 9:22:08 hrs 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
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