Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: 2 1 -2 -1 2 1 -2 -1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when add 3 to it, completely divided 8, 12 and 18 is? 70 69 71 68 70 69 71 68 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10080 10010 10015 10020 10080 10010 10015 10020 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
Problems on H.C.F and L.C.M What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? 40 30 56 36 40 30 56 36 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds 46 minutes and 12 seconds 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 200 40 120 80 200 40 120 80 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
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