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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:

322
345
276
299

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.

Problems on H.C.F and L.C.M
The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is :

9893
8739
9834
9831

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Five bells ring together and ring at intervals of 2, 6, 8, 12 and 15 seconds respectively. How many times will they ring together in 60 minutes?

31
33
34
32

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

17/29
31/45
11/13
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

64
28
32
40

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number of four digits which is exactly divisible by 27,18,12,15

11720
9720
10720
8720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720

MORE MCQ ON Problems on H.C.F and L.C.M

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