Problems on H.C.F and L.C.M The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: 322 345 299 276 322 345 299 276 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.
Problems on H.C.F and L.C.M A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose? 391 431 485 381 391 431 485 381 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 601/55 55/601 120/11 11/120 601/55 55/601 120/11 11/120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 910 1001 91 1911 910 1001 91 1911 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 45 minutes 46 minutes and 12 seconds 42 minutes and 36 seconds 26 minutes and 18 seconds 45 minutes 46 minutes and 12 seconds 42 minutes and 36 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Find the H.C.F. of 513, 1134 and 1215. 42 63 27 58 42 63 27 58 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1134 ) 1215 ( 1 1134 --------- 81 ) 1134 ( 14 81 --------- 324 324 --------- x ---------- H.C.F. of 1134 and 1215 is 81.So, Required H.C.F. = H.C.F. of 513 and 81. ______81 ) 513 ( 6 __486____ 27) 81 ( 3 81 0H.C.F. of given numbers = 27.
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