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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder?

5016
5054
5035
5073

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

1383
1983
1183
1683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.

Problems on H.C.F and L.C.M
Find the H.C.F of 54/9, 3 9/17 and 36/51?

6/153
17/6
6
17

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

4
5
3
6

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

18002
17004
18004
18000

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

360
420
180
110

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

MORE MCQ ON Problems on H.C.F and L.C.M

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