Problems on H.C.F and L.C.M
Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder?
Converting given measurements into centimeters 4m 96 cm = 400+96 = 496 cm 4m 3cm = 400+3 =403 cmTo find the side of the largest possible brick , the side of brick must divide length as well as breadth exactly. Using division method 403)496(1 403 93) 403 (4 370 31) 93 (3 93 0HCF = 31 Side of the largest possible square brick =31cm
EXAMIANS