Problems on H.C.F and L.C.M Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder? 5073 5054 5016 5035 5073 5054 5016 5035 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 20 30 40 10 20 30 40 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Find the L.C.M. of 16, 24, 36 and 54. 228 321 432 189 228 321 432 189 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 16 - 24 - 36 - 54----------------------------- 2 | 8 - 12 - 18 - 27----------------------------- 2 | 4 - 6 - 9 - 27 --------------------------- 2 | 2 - 3 - 9 - 27 -------------------------- 2 | 1 - 3 - 9 - 27-------------------------- 3 | 1 - 1 - 3 - 9--------------------------- 3 | 1 - 1 - 1 - 3 L.C.M. = 2 x 2 x 2 x 3 x 3 x 2 x 3 = 432.
Problems on H.C.F and L.C.M The H.C.F of 204, 1190 and 1445 is: 19 18 21 17 19 18 21 17 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 1 minute 48 seconds 2 minute 48 seconds 3 minute 48 seconds 4 minute 48 seconds 1 minute 48 seconds 2 minute 48 seconds 3 minute 48 seconds 4 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work? 39 40 37 35 39 40 37 35 ANSWER DOWNLOAD EXAMIANS APP
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