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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number?

29
23
17
31

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively

133
131
129
127

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127

Problems on H.C.F and L.C.M
The least number which when increased by 5 each divisible by each one of 24, 32, 36 and 54 is :

869
859
4320
427

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively.

3024
3036
3002
3013

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which of the following has the most number of divisors?

101
182
99
176

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.Option B, 182 = 1 x 2 x 7 x 13. Option C, 99 = 1 x 3 x 3 x 11. Option D, 101 = 1 x 101.Divisors of 99 are 1, 3, 9, 11, 33, 99.Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176. Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.Hence, 176 have the most number of divisors.

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

2
4
6
8

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

MORE MCQ ON Problems on H.C.F and L.C.M

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