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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the largest number which divides 62,132,237 to leave the same reminder

25
35
30
None of these

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Trick is HCF of (237-132), (132-62), (237-62)= HCF of (70,105,175) = 35

Problems on H.C.F and L.C.M
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

1745
777
364
1045

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

308
208
508
408

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other number = (11 x 7700/275) = 308.

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is:

90
10
46
70

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

17/29
11/13
31/45
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is :

64
124
124
260

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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