Problems on H.C.F and L.C.M The H.C.F of 204, 1190 and 1445 is: 19 17 18 21 19 17 18 21 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 120/11 601/55 55/601 11/120 120/11 601/55 55/601 11/120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 21 22 24 23 21 22 24 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively. 3036 3024 3013 3002 3036 3024 3013 3002 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 87 and 145 is: 875 48 1305 435 875 48 1305 435 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Express 1168/1095 in simple form? 19/18 17/16 18/17 16/15 19/18 17/16 18/17 16/15 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To express any fraction in simple (small form), we have to find the HCF of numerator and denominator. 1095)1168(1 1095 73)1095(15 1095 ——— 0 HCF of 1095 and 1168 is 73Therefore (1168/73)/(1095/73) = 16/15
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