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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

18
19
16
17

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF of (400-9, 435-10, 541-14)HCF of (391, 425, 527) = 17

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively.

3002
3024
3013
3036

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

48
36
18
24

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.

Problems on H.C.F and L.C.M
The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is :

2523
3363
1683
1677

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1394
1294
1494
1194

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

9720
7720
6720
8720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

MORE MCQ ON Problems on H.C.F and L.C.M

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