Problems on H.C.F and L.C.M Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively. 10750 10570 10075 17050 10750 10570 10075 17050 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is: 108 48 84 12 108 48 84 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are: 4, 8, 12 5, 10, 15 10, 20, 30 10, 20, 30 4, 8, 12 5, 10, 15 10, 20, 30 10, 20, 30 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 17 19 16 18 17 19 16 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: 2 1 -1 -2 2 1 -1 -2 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? 4 10 15 16 4 10 15 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2