The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:

Problems on H.C.F and L.C.M
The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:

1440

1449

1459

1439

1440

1449

1459

1439

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Problems on H.C.F and L.C.M
Express 1168/1095 in simple form?

19/18

17/16

16/15

18/17

19/18

17/16

16/15

18/17

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Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

101

107

185

111

101

107

185

111

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Problems on H.C.F and L.C.M
LCM of 18 and 27 is:

85

54

91

89

85

54

91

89

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Problems on H.C.F and L.C.M
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

1

2

-1

-2

1

2

-1

-2

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Problems on H.C.F and L.C.M
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

800,500

700,400

820,369

820,360

800,500

700,400

820,369

820,360

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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:

Problems on H.C.F and L.C.M Express 1168/1095 in simple form?

Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Problems on H.C.F and L.C.M LCM of 18 and 27 is:

Problems on H.C.F and L.C.M L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

Problems on H.C.F and L.C.M
The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:

Problems on H.C.F and L.C.M
Express 1168/1095 in simple form?

Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Problems on H.C.F and L.C.M
LCM of 18 and 27 is:

Problems on H.C.F and L.C.M
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

Problems on H.C.F and L.C.M
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?