Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9800 9000 9400 9600 9800 9000 9400 9600 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is 5 4 3 6 5 4 3 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 601/55 55/601 11/120 120/11 601/55 55/601 11/120 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1459 1440 1439 1449 1459 1440 1439 1449 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is 180 1260 540 360 180 1260 540 360 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 6 4 8 2 6 4 8 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
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