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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number of four digits which is divisible by 15, 25, 40 and 75 is:

9000
9800
9600
9400

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again?

246 seconds
240 seconds
242 seconds
243 seconds

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Which of the following has the most number of divisors?

101
176
99
182

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.Option B, 182 = 1 x 2 x 7 x 13. Option C, 99 = 1 x 3 x 3 x 11. Option D, 101 = 1 x 101.Divisors of 99 are 1, 3, 9, 11, 33, 99.Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176. Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.Hence, 176 have the most number of divisors.

Problems on H.C.F and L.C.M
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

6
5
4
3

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Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 2 x 2 x 3 x 7
2 x 3 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7
2 x 2 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
Five bells ring together and ring at intervals of 2, 6, 8, 12 and 15 seconds respectively. How many times will they ring together in 60 minutes?

31
34
32
33

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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