Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9000 9600 9800 9400 9000 9600 9800 9400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M The product of two numbers is 1320 and their H.C.F. is 6. the L.C.M. of the numbers is: 1314 7920 220 1326 1314 7920 220 1326 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 6 minutes 8 minutes 5 minutes 7 minutes 6 minutes 8 minutes 5 minutes 7 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 3 5 6 4 3 5 6 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the L.C.M.. of 72, 108 and 2100. 38000 37000 38600 37800 38000 37000 38600 37800 ANSWER DOWNLOAD EXAMIANS APP
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