Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9000 9600 9800 9400 9000 9600 9800 9400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: 15120 15110 11115 15210 15120 15110 11115 15210 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of 0.54, 1.8 and 7.2 is: 18 1.8 0.018 0.18 18 1.8 0.018 0.18 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 31 24 17 21 31 24 17 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: 24 48 36 18 24 48 36 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 420 180 360 110 420 180 360 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
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