Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9600 9800 9400 9000 9600 9800 9400 9000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 12 : 31 am 11 : 31 am 10 : 31 am 9 : 31 am 12 : 31 am 11 : 31 am 10 : 31 am 9 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Problems on H.C.F and L.C.M A rectangular courtyard 3.78 metres long and 2.25 metres wide is to be paved exactly with square title, all of the same size. What is the largest size of the tile which could be used for the purpose 11 cms None of these 21 cms 42 cms 11 cms None of these 21 cms 42 cms ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 100 98 97 99 100 98 97 99 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 0, 62,98 and 130 as remainders respectively is . 15110 15210 11115 15120 15110 15210 11115 15120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 601/55 55/601 120/11 11/120 601/55 55/601 120/11 11/120 ANSWER DOWNLOAD EXAMIANS APP
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