Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 389 216 443 548 389 216 443 548 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is: 40 60 30 20 40 60 30 20 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is: 50/294 60/147 30/98 30/7 50/294 60/147 30/98 30/7 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 859 869 427 4320 859 869 427 4320 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 21 24 17 31 21 24 17 31 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? 66 36 132 264 66 36 132 264 ANSWER DOWNLOAD EXAMIANS APP
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