Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 216 548 389 443 216 548 389 443 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M What is the HCF of 2/3, 4/9 and 6/5 8/45 2/45 7/45 4/15 8/45 2/45 7/45 4/15 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 243 seconds 246 seconds 240 seconds 242 seconds 243 seconds 246 seconds 240 seconds 242 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 6 : 27 : 12 hrs. 8 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 8 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 116 121 112 123 116 121 112 123 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10020 10010 10015 10080 10020 10010 10015 10080 ANSWER DOWNLOAD EXAMIANS APP
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