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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

548
216
389
443

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:

40
32
28
64

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is:

260
64
124
156

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again?

240 seconds
243 seconds
246 seconds
242 seconds

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

8720
6720
9720
7720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

Problems on H.C.F and L.C.M
The leas number which when divided by 5, 6, 7 and 8 leaves a remainder 3 but when divided by 9 leaves no remainder, is :

2523
3363
1683
1677

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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