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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

443
216
389
548

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.

Problems on H.C.F and L.C.M
If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

77
55
88
66

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99)                              = 77

Problems on H.C.F and L.C.M
The Smallest number which when diminished by 7, is divisible by 12,16,18,21 and 28 is :

1032
1015
1022
1008

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm.

25 cm
35 cm
45 cm
55 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required length = H.C.F. of 495 cm, 900 cm and 1665 cm.          495 = 3² x 5 x 11, 900 = 2² x 3² x 5², 1665 = 3² x 5 x 37.      H.C.F. = 32 x 5 = 45.          Hence, required length = 45 cm.

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

9720
12765
11340
10478

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

Problems on H.C.F and L.C.M
Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively.

3024
3013
3002
3036

ANSWER DOWNLOAD EXAMIANS APP
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