• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

216
443
389
548

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively.

3002
3024
3013
3036

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is:

14400
1600
3600
6400

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

Cannot be calculated
117
F
1
equal to their H.

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

3683
1683
2683
4683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5,6,7,8 = 840.    Required number is of the form 840k + 3     Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683

Problems on H.C.F and L.C.M
The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is :

23
13
3
33

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑