Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 216 389 548 443 216 389 548 443 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again? 246 seconds 240 seconds 242 seconds 243 seconds 246 seconds 240 seconds 242 seconds 243 seconds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 1260 360 540 180 1260 360 540 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 10 16 15 4 10 16 15 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 0.12, 0.15, 0.2 and 0.54? 9.2 2.8 7.8 5.4 9.2 2.8 7.8 5.4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Make the number of decimal places in all the given numbers the same i.e., 0.12, 0.15, 0.2 and 0.54LCM of 12, 15, 20 and 542|12 15 20 542|6 15 10 273|3 15 5 275|1 5 5 9 1 1 1 9LCM=22×3×5×9=540 LCM=540/10 =5.4
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 127 131 133 129 127 131 133 129 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
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