Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 389 443 216 548 389 443 216 548 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M Find the L.C.M. of 16, 24, 36 and 54. 432 321 228 189 432 321 228 189 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 | 16 - 24 - 36 - 54----------------------------- 2 | 8 - 12 - 18 - 27----------------------------- 2 | 4 - 6 - 9 - 27 --------------------------- 2 | 2 - 3 - 9 - 27 -------------------------- 2 | 1 - 3 - 9 - 27-------------------------- 3 | 1 - 1 - 3 - 9--------------------------- 3 | 1 - 1 - 1 - 3 L.C.M. = 2 x 2 x 2 x 3 x 3 x 2 x 3 = 432.
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1001 1911 91 910 1001 1911 91 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 10 16 4 15 10 16 4 15 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is : 3 33 13 23 3 33 13 23 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 55/601 11/120 120/11 601/55 55/601 11/120 120/11 601/55 ANSWER DOWNLOAD EXAMIANS APP
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