Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 389 443 548 216 389 443 548 216 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M Find the greatest number that will divided 43,91 and 183 so as to leave the same remainder in each case 13 9 7 4 13 9 7 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder? 5054 5035 5073 5016 5054 5035 5073 5016 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the greatest number which divides 29, 32, 38 and leaves same remainder in each case? 2 4 5 3 2 4 5 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of two numbers is 42 and the other two factors of their LCM are 11 and 12. What is the largest number. 480 462 504 450 480 462 504 450 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? 15 16 10 4 15 16 10 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2
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