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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

389
443
216
548

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.

Problems on H.C.F and L.C.M
Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers?

76
56
48
84

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the H.C.F of 54/9, 3 9/17 and 36/51?

17
17/6
6/153
6

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is:

-2
1
2
-1

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

8
4
6
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)                                 = H.C.F. of 48, 92 and 140 = 4.

Problems on H.C.F and L.C.M
Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm.

45 cm
55 cm
25 cm
35 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required length = H.C.F. of 495 cm, 900 cm and 1665 cm.          495 = 3² x 5 x 11, 900 = 2² x 3² x 5², 1665 = 3² x 5 x 37.      H.C.F. = 32 x 5 = 45.          Hence, required length = 45 cm.

MORE MCQ ON Problems on H.C.F and L.C.M

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