Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1294 1494 1394 1194 1294 1494 1394 1194 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is? 1496 1494 1994 1349 1496 1494 1994 1349 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 180 540 1260 360 180 540 1260 360 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 107 101 111 185 107 101 111 185 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M What is the smallest number which when diminished by 8, is divisible by 9, 6, 12 and 18? 50 45 60 44 50 45 60 44 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is 25 cm 15 cm 42 cm 35 cm 25 cm 15 cm 42 cm 35 cm ANSWER DOWNLOAD EXAMIANS APP