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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1394
1194
1494
1294

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

37
39
35
40

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is:

4
3
5
6

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

10478
12765
11340
9720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

Problems on H.C.F and L.C.M
The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:

25 cm
55 cm
45 cm
35 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.

Problems on H.C.F and L.C.M
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

128
126
125
127

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.

MORE MCQ ON Problems on H.C.F and L.C.M

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