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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1294
1494
1394
1194

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?

1496
1494
1994
1349

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is:

180
540
1260
360

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

107
101
111
185

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

Problems on H.C.F and L.C.M
What is the smallest number which when diminished by 8, is divisible by 9, 6, 12 and 18?

50
45
60
44

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is

25 cm
15 cm
42 cm
35 cm

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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