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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1394
1294
1194
1494

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 2 x 3 x 3 x 7
2 x 2 x 2 x 3 x 7
2 x 3 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 12 and their difference is 12. The numbers are:

70, 82
66, 78
84, 96
94, 106

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is:

48
108
12
84

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
LCM of 1/3, 5/6, 5/4, 10/7 is:

10/11
10
11/10
10/7

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

4
6
5
3

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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