Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 126 125 128 127 126 125 128 127 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 21 17 31 24 21 17 31 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M The product of two numbers is 2025 and their HCF is 15 their LCM is: 2010 2040 150 135 2010 2040 150 135 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: 15110 15120 15210 11115 15110 15120 15210 11115 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 45 times their H.C.F. If one of the numbers is 125 and the sum of H.C.F. and L.C.M. is 1150, the other number is: 225 235 220 215 225 235 220 215 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS