Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 128 125 127 126 128 125 127 126 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is: 200 40 80 120 200 40 80 120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number of four digits that have 144 for their HCF is? 9903 9936 9935 9930 9903 9936 9935 9930 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is: 25 cm 55 cm 35 cm 45 cm 25 cm 55 cm 35 cm 45 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: Cannot be calculated equal to their H. 117 F 1 Cannot be calculated equal to their H. 117 F 1 ANSWER DOWNLOAD EXAMIANS APP
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