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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the H.C.F of 12, 16, 18 and 24?

3
4
1
2

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number of five digits which is exactly divisible by 12,15 and 18 is :

10020
10015
10080
10010

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 NA

Problems on H.C.F and L.C.M
The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:

1449
1439
1440
1459

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

36
24
18
48

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.So, the numbers 12 and 16.L.C.M. of 12 and 16 = 48.

Problems on H.C.F and L.C.M
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

1383
1683
1983
1183

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.

Problems on H.C.F and L.C.M
Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case

404
707
505
606

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

  3 |  6 - 7  - 8  - 9 - 12-----------------------------  4 | 2  - 7  - 8  - 3 - 4  ---------------------------   2 | 2  - 7  - 2  - 3 - 1 --------------------------     | 1  - 7  - 1  - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505   

MORE MCQ ON Problems on H.C.F and L.C.M

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