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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is:

3
4
5
6

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Least perfect square number, exactly divisible by 21, 36 and 56 is?

7056
504
441
3600

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

18004
17004
18000
18002

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 4128/4386 to its lowest terms

14/13
13/17
16/17
13/18

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Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

23/37
31/45
17/29
11/13

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
Find the lowest common multiple of 24, 36 and 40.

120
240
360
480

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.

MORE MCQ ON Problems on H.C.F and L.C.M

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