Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 4 6 5 3 4 6 5 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1194 1394 1494 1294 1194 1394 1494 1294 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 25 23 21 27 25 23 21 27 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
Problems on H.C.F and L.C.M The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 10 90 70 46 10 90 70 46 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is: 10 90 70 46 10 90 70 46 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is : 64 260 124 124 64 260 124 124 ANSWER DOWNLOAD EXAMIANS APP
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