Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 3 5 4 6 3 5 4 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 11/13 23/37 31/45 17/29 11/13 23/37 31/45 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is: 4 12 6 8 4 12 6 8 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29, and 34 respectively . 1394 1354 1384 1295 1394 1354 1384 1295 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point. 26 minutes 18 seconds 45 minutes 42 minutes 36 seconds 46 minutes 12 seconds. 26 minutes 18 seconds 45 minutes 42 minutes 36 seconds 46 minutes 12 seconds. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds 45 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
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