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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

208
308
408
508

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Other number = (11 x 7700/275) = 308.

Problems on H.C.F and L.C.M
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

777
364
1745
1045

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.

Problems on H.C.F and L.C.M
The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers.

8 and 10
8 and 6
2 and 4
6 and 4

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

601/55
55/601
120/11
11/120

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively.

3002
3036
3024
3013

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

19
17
16
18

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF of (400-9, 435-10, 541-14)HCF of (391, 425, 527) = 17

MORE MCQ ON Problems on H.C.F and L.C.M

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