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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respestively.

3002
3013
3036
3024

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the H.C.F of 204, 1190 and 1445?

204
85
17
34

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

39
40
35
37

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is:

6
5
3
4

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is:

30/98
50/294
60/147
30/7

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

11/13
17/29
31/45
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

MORE MCQ ON Problems on H.C.F and L.C.M

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