Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 17/29 31/45 11/13 23/37 17/29 31/45 11/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is 180 360 1260 540 180 360 1260 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? 15 16 10 4 15 16 10 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2
Problems on H.C.F and L.C.M Five bells ring together and ring at intervals of 2, 6, 8, 12 and 15 seconds respectively. How many times will they ring together in 60 minutes? 33 31 34 32 33 31 34 32 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : 4 5 3 6 4 5 3 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is: 64 260 156 124 64 260 156 124 ANSWER DOWNLOAD EXAMIANS APP
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