Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 11/13 17/29 23/37 31/45 11/13 17/29 23/37 31/45 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 910 1001 91 1911 910 1001 91 1911 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder? 210 126 119 154 210 126 119 154 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm. 25 cm 45 cm 55 cm 35 cm 25 cm 45 cm 55 cm 35 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 495 cm, 900 cm and 1665 cm. 495 = 3² x 5 x 11, 900 = 2² x 3² x 5², 1665 = 3² x 5 x 37. H.C.F. = 32 x 5 = 45. Hence, required length = 45 cm.
Problems on H.C.F and L.C.M The H.C.F. of 1.75, 5.6 and 7 is: 0.35 3.5 0.7 0.07 0.35 3.5 0.7 0.07 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 182 101 99 176 182 101 99 176 ANSWER DOWNLOAD EXAMIANS APP
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