Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 11/13 23/37 17/29 31/45 11/13 23/37 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case. 22 35 52 48 22 35 52 48 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62) = H.C.F. of 70, 105 and 175 = 35.
Problems on H.C.F and L.C.M Find the smallest number which when increased by 5, divisible by 6, 9, 15, 20 and 24? 377 344 366 355 377 344 366 355 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10010 10020 10015 10080 10010 10020 10015 10080 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
Problems on H.C.F and L.C.M The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers. 8 and 6 2 and 4 6 and 4 8 and 10 8 and 6 2 and 4 6 and 4 8 and 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16,20, and 24, is : 1600 6400 3600 11400 1600 6400 3600 11400 ANSWER DOWNLOAD EXAMIANS APP
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