Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 17/29 23/37 11/13 31/45 17/29 23/37 11/13 31/45 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 7 9 4 13 7 9 4 13 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits that have 144 their HCF is? 10070 10075 10080 10085 10070 10075 10080 10085 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm. 35 cm 45 cm 55 cm 25 cm 35 cm 45 cm 55 cm 25 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 495 cm, 900 cm and 1665 cm. 495 = 3² x 5 x 11, 900 = 2² x 3² x 5², 1665 = 3² x 5 x 37. H.C.F. = 32 x 5 = 45. Hence, required length = 45 cm.
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 46 minutes and 12 seconds 26 minutes and 18 seconds 42 minutes and 36 seconds 45 minutes 46 minutes and 12 seconds 26 minutes and 18 seconds 42 minutes and 36 seconds 45 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18000 17004 18002 18004 18000 17004 18002 18004 ANSWER DOWNLOAD EXAMIANS APP
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