Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 17/29 11/13 23/37 31/45 17/29 11/13 23/37 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is : 8739 9834 9893 9831 8739 9834 9893 9831 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A rectangular courtyard 3.78 metres long and 2.25 metres wide is to be paved exactly with square title, all of the same size. What is the largest size of the tile which could be used for the purpose 11 cms 21 cms 42 cms None of these 11 cms 21 cms 42 cms None of these ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose? 391 381 485 431 391 381 485 431 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 982 995 1024 893 982 995 1024 893 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1494 1194 1294 1394 1494 1194 1294 1394 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
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