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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

31/45
11/13
17/29
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

17
18
16
19

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF of (400-9, 435-10, 541-14)HCF of (391, 425, 527) = 17

Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

11/120
55/601
120/11
601/55

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

123
112
116
121

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
The least number of five digits which is exactly divisible by 12,15 and 18 is :

10020
10010
10080
10015

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 NA

Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at intervals of 2,4,6,8,10 and 12 seconds respectively. in 30 m9nutes,how many times do they toll together ?

15
4
16
10

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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