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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

17/29
11/13
23/37
31/45

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.

2474
2574
2774
2674

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

HCF * LCM = 84942, because we knowProduct of two numbers = Product of HCF and LCMLCM = 84942/33 = 2574

Problems on H.C.F and L.C.M
The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is :

91
1001
1911
910

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

420
180
360
110

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

Problems on H.C.F and L.C.M
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is:

3600
6400
14400
1600

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is:

3
6
4
5

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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