Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 23/37 11/13 17/29 31/45 23/37 11/13 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 540 360 180 1260 540 360 180 1260 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 40 10 30 20 40 10 30 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is 6 3 4 5 6 3 4 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? 264 66 36 132 264 66 36 132 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 295, 243 195, 143 95, 43 395, 343 295, 243 195, 143 95, 43 395, 343 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
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