Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 17/29 31/45 23/37 11/13 17/29 31/45 23/37 11/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 1024 995 893 982 1024 995 893 982 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is: 55 cm 35 cm 45 cm 25 cm 55 cm 35 cm 45 cm 25 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 17 24 31 21 17 24 31 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 689 268 432 1015 689 268 432 1015 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M The H.C.F. of 0.54, 1.8 and 7.2 is: 0.018 1.8 18 0.18 0.018 1.8 18 0.18 ANSWER DOWNLOAD EXAMIANS APP
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