Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 17/29 31/45 11/13 23/37 17/29 31/45 11/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is 8739 9834 9831 9893 8739 9834 9831 9893 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case 7 13 4 9 7 13 4 9 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1001 91 1911 910 1001 91 1911 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is 360 540 1260 180 360 540 1260 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 66 77 88 55 66 77 88 55 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
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