Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 11/13 23/37 17/29 31/45 11/13 23/37 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 8720 8760 9720 9620 8720 8760 9720 9620 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is 12 6 4 8 12 6 4 8 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M LCM of 455, 117, 338 is: 10670 104670 106470 107470 10670 104670 106470 107470 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F of 204, 1190 and 1445 is: 19 21 18 17 19 21 18 17 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 46 minutes and 12 seconds 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds 46 minutes and 12 seconds 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
EXAMIANS