Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1020 1030 1026 1022 1020 1030 1026 1022 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: 1745 1045 364 777 1745 1045 364 777 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 15/16 25/26 13/16 17/26 15/16 25/26 13/16 17/26 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of 22, 54, 108, 135 and 198 is 1980 330 5940 11880 1980 330 5940 11880 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1001 1911 91 910 1001 1911 91 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 10720 11720 8720 9720 10720 11720 8720 9720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
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