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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

1030
1020
1022
1026

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

18000
18004
18002
17004

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

2
1
-1
-2

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

48
875
1305
435

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

110
360
180
420

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

Problems on H.C.F and L.C.M
Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

120
80
200
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.

MORE MCQ ON Problems on H.C.F and L.C.M

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