Problems on H.C.F and L.C.M What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? 36 30 56 40 36 30 56 40 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1095 1085 1080 1075 1095 1085 1080 1075 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of 22, 54, 108, 135 and 198 is 1980 11880 5940 330 1980 11880 5940 330 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 19 18 16 17 19 18 16 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (12,180) (72,30) (36,60) (96,25) (12,180) (72,30) (36,60) (96,25) ANSWER DOWNLOAD EXAMIANS APP
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