Problems on H.C.F and L.C.M What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? 56 30 40 36 56 30 40 36 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 40 30 20 10 40 30 20 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is: 8 6 12 4 8 6 12 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 445 379 127 221 445 379 127 221 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
Problems on H.C.F and L.C.M Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? 1022 1020 1026 1030 1022 1020 1026 1030 ANSWER DOWNLOAD EXAMIANS APP
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