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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

689
268
432
1015

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

Problems on H.C.F and L.C.M
Find the HCF of 2.1, 1.05 and 0.63

0.21
2.21
3.21
1.21

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21

Problems on H.C.F and L.C.M
The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is:

16
12
48
24

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

123
116
112
121

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
What is the smallest number which when diminished by 8, is divisible by 9, 6, 12 and 18?

60
50
45
44

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ?

10
16
4
15

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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