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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

432
689
268
1015

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

Problems on H.C.F and L.C.M
H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is

360
540
180
1260

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

6
4
5
3

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:

5, 10, 15
10, 20, 30
4, 8, 12
10, 20, 30

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is:

120
80
40
200

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

30
10
20
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

MORE MCQ ON Problems on H.C.F and L.C.M

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