Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 268 1015 689 432 268 1015 689 432 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder? 210 126 154 119 210 126 154 119 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the highest common factor of 36 and 84. 22 34 16 12 22 34 16 12 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 36 = 2² x 3²84 = 2² x 3 x 7H.C.F. = 2² x 3 = 12.
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number? 13 5 11 7 13 5 11 7 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number which when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20 respectively? 68 58 None 78 68 58 None 78 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 22 21 23 24 22 21 23 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
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