Problems on H.C.F and L.C.M The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is 9834 9831 9893 8739 9834 9831 9893 8739 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : 5 6 4 3 5 6 4 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 508 208 308 408 508 208 308 408 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: 1983 1683 1183 1383 1983 1683 1183 1383 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 24 22 21 23 24 22 21 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (12,180) (72,30) (36,60) (96,25) (12,180) (72,30) (36,60) (96,25) ANSWER DOWNLOAD EXAMIANS APP
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