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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is

8739
9834
9831
9893

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the smallest number of five digits exactly divisible by 16,24,36 and 54.

10268
10568
10368
10468

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Smallest number of five digits is 10000.       Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432,       On dividing 10000 by 432,we get 64 as remainder.    Required number = 10000 +( 432 – 64 ) = 10368.

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1294
1194
1494
1394

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

31/45
23/37
17/29
11/13

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

2683
4683
1683
3683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5,6,7,8 = 840.    Required number is of the form 840k + 3     Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683

Problems on H.C.F and L.C.M
Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is:

200
120
80
40

ANSWER DOWNLOAD EXAMIANS APP
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