Problems on H.C.F and L.C.M The largest four – digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is 9893 9831 8739 9834 9893 9831 8739 9834 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest possible length which can be used to measure exactly the length 4 m 95 cm . , 9 m and 16 m 65 cm. 45 cm. 42 cm. 35 cm 55 cm. 45 cm. 42 cm. 35 cm 55 cm. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 111 185 107 101 111 185 107 101 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is: 80 120 40 200 80 120 40 200 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 23 27 25 21 23 27 25 21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
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