Problems on H.C.F and L.C.M The least square number which divides 8, 12 and 18 is? 121 144 64 100 121 144 64 100 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 8 : 27 : 12 hrs. 7 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 8 : 27 : 12 hrs. 7 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 0, 62,98 and 130 as remainders respectively is . 15210 11115 15120 15110 15210 11115 15120 15110 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number? 17 23 31 29 17 23 31 29 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the LCM of 8, 24, 36 and 54 216 444 345 112 216 444 345 112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 8-24-36-54 will be2*2*2*3*3*3 = 216
Problems on H.C.F and L.C.M Find the smallest number of five digits exactly divisible by 16,24,36 and 54. 10468 10568 10368 10268 10468 10568 10368 10268 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Smallest number of five digits is 10000. Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432, On dividing 10000 by 432,we get 64 as remainder. Required number = 10000 +( 432 – 64 ) = 10368.
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