Problems on H.C.F and L.C.M The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is: 48 24 16 12 48 24 16 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is: 32 64 40 28 32 64 40 28 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 268 432 689 1015 268 432 689 1015 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? 56 36 30 40 56 36 30 40 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 1260 180 360 540 1260 180 360 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 42 minutes and 36 seconds 26 minutes and 18 seconds 45 minutes 46 minutes and 12 seconds 42 minutes and 36 seconds 26 minutes and 18 seconds 45 minutes 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.