Problems on H.C.F and L.C.M Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 17004 18002 18004 18000 17004 18002 18004 18000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is : 33 23 3 13 33 23 3 13 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 60 150 180 110 60 150 180 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 308 408 508 208 308 408 508 208 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is: 180 360 1260 540 180 360 1260 540 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 21 27 25 23 21 27 25 23 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
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