MGVCL Exam Paper (30-07-2021 Shift 3) Which of the following medium is used between CPU and RAM to speed up the processing power of a CPU? Virtual memory Flash memory DRAM Cache memory Virtual memory Flash memory DRAM Cache memory ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) નીચે પૈકી 'ઓસોડ' નો સમાનર્થી શબ્દ કયો છે? વૃંદા અમર અનરવું ઔષધ વૃંદા અમર અનરવું ઔષધ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 400 W and -50 W. Calculate the reactive power taken by the load 350/√3 VAR 450√3 VAR 350√3 VAR 450/√3 VAR 350/√3 VAR 450√3 VAR 350√3 VAR 450/√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken (Q) = √3*(W1 - W2)= √3*(450 + 50)= √3*450 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) દ્રશ્ય' શબ્દનો વિરુદ્ધાર્થ શબ્દ આપેલો વિકલ્પોમાંથી કયો છે? દ્રષ્ટિવંત દ્રષ્ટિ દ્રશ્યમાન અદ્રશ્ય દ્રષ્ટિવંત દ્રષ્ટિ દ્રશ્યમાન અદ્રશ્ય ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in Second Generation Computers First Generation Computers Fourth Generation Computers Third Generation Computers Second Generation Computers First Generation Computers Fourth Generation Computers Third Generation Computers ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.4 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 0.8 Hz 1.8 Hz 1.6 Hz 1.2 Hz 0.8 Hz 1.8 Hz 1.6 Hz 1.2 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (1.1/0.6)*cosδ= (1.1/0.6)*0.5= 0.91M = (H*s)/(πf)= 4/(50π)fn = (0..91/(4/50π))= 8.9 rad/sec= 1.2 Hz
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