MGVCL Exam Paper (30-07-2021 Shift 3) What is the value of the characteristic impedance of a transmission line with impedance and admittance of 15 and 5? 1.732 1.414 0.7.7 0.577 1.732 1.414 0.7.7 0.577 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Characteristic impedance = √(impedance/admittance) = 1.73
MGVCL Exam Paper (30-07-2021 Shift 3) A 10-pole induction motor is supplied by a 6-pole alternator, which is driven at 1400 rpm. If the motor runs with a slip of 5%, what is its speed? 882 rpm 1575 rpm 1425 rpm 798 rpm 882 rpm 1575 rpm 1425 rpm 798 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Slip of the induction motor,S = (Ns - Nr)/NsNs = (120*f)/PPoles (P) = 61400 = (120*f)/6f = 70 HzFor P = 10Ns = (120*70)/10= 840 rpmNr = Ns(1 - S)= 840*(1 - 0.05)= 798 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) A 200/400 V, 20 kVA, 2-winding transformer is connected as an auto-transformer to transform 600 V to 200 V. Calculate the kVA rating of the auto-transformer. 60 kVA 25 kVA 30 kVA 50 kVA 60 kVA 25 kVA 30 kVA 50 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here auto transformer change voltage from 600 V to 200 V.Voltage ratio (a) = 600/200 = 3kVA rating of the auto-transformer = (a/(a - 1))*(kVA rating of auto transformer)= (3/2)*20= 30 kVA
MGVCL Exam Paper (30-07-2021 Shift 3) The sending end and receiving end voltages of the short transmission line are 150 kV and 120 kV respectively. Calculate its percentage voltage regulation. 20% 30% 40% 25% 20% 30% 40% 25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,Vs - sending end voltage in kVVr - Receiving end voltage in kV.Voltage regulation = (Vs - Vr)/Vr= (150 - 120)/120= 0.25% R = 25 %
MGVCL Exam Paper (30-07-2021 Shift 3) સારું:નરસું::શુક્લ: ? અમર અવિશાની કૃષ્ણ પરમ અમર અવિશાની કૃષ્ણ પરમ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) સાબરમતી: અમદાવાદ:: મૂસી: ગોવા વેનિસ લંડન હૈદરાબાદ ગોવા વેનિસ લંડન હૈદરાબાદ ANSWER DOWNLOAD EXAMIANS APP
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