MGVCL Exam Paper (30-07-2021 Shift 3) Choose the word which best expresses the similar meaning of the given word "ABDICATE" Pursue Continue Treasure Relinquish Pursue Continue Treasure Relinquish ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Name the application under MS Office software bundle, that we use to create audio- visual presentation. MS Word MS Access MS Excel MS Power point MS Word MS Access MS Excel MS Power point ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Continuous and rapid variations in the load current magnitude which causes voltage variations is known as Voltage sag Voltage distortion Flicker Harmonics Voltage sag Voltage distortion Flicker Harmonics ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When voltage changes occur in rapid succession, with magnitudes large enough to cause lighting level variations.The human eye-brain response is most sensitive to periodic r.m.s. voltage changes that occur at around 8 - 10 cycles per second.
MGVCL Exam Paper (30-07-2021 Shift 3) If a cable of homogeneous insulation has maximum stress of 6 kV/mm, then the dielectric strength of insulation should be ____ 6 kv/mm 12 kV/mm 1.5 kV/mm 3 kV/mm 6 kv/mm 12 kV/mm 1.5 kV/mm 3 kV/mm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP If a cable have homogeneous insulation then the dielectric strength of insulation should be is equal to maximum dielectric strength.
MGVCL Exam Paper (30-07-2021 Shift 3) Fill in the blanks with suitable Preposition from the given alternatives.BCCI receives____1000 applications for Team India head coach position over for since against over for since against ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.73 H and 13.85 pF 0.53 H and 15.83 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.73 H and 13.85 pF 0.53 H and 15.83 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
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