MGVCL Exam Paper (30-07-2021 Shift 3) Choose the best option from the given alternatives which can be substituted for the given word/sentence.Code of diplomatic etiquette and precedence Sheath Secular Protocol Wardrobe Sheath Secular Protocol Wardrobe ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A three phase four pole 50 Hz induction motor has a rotor resistance of 0.02 Ω/phase and stand-still reactance of 0.5 Ω/phase. Calculate the speed at which the maximum torque is developed. 1500 rpm 1475 rpm 1440 rpm 1525 rpm 1500 rpm 1475 rpm 1440 rpm 1525 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Condition for maximum torque,Sm = R2/X2= 0.04Ns = (120*f)/P= (120*50)/4= 1500 rpmS = (Ns - Nr)/NsNr = Ns(1 - Sm)= 1500*(1 - 0.04)= 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) Data Encryption Standard (DES) was designed by Microsoft IBM None of these Apple Microsoft IBM None of these Apple ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The complex power injections at a bus are shown in figure Two lines connected drawing the powers as shown in figure. The complex power in the line-2 "S2" is 2+j1 2+j5 2-j5 2-j1 2+j1 2+j5 2-j5 2-j1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Total power generate (Sg) = S1 + S2S2 = Sg - S1= 5 + 3j - 3 + 2j= 2 + 5j
MGVCL Exam Paper (30-07-2021 Shift 3) હું અહી આવી શકું' વાક્યને સ્થળવાચક ક્રીયાવીશેષણમાં ફેરવો. હું આજે નહિ આવી શકું. હું નિયમિત રીતે અહી આવી શકું. હું કદી પણ નહિ આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. હું આજે નહિ આવી શકું. હું નિયમિત રીતે અહી આવી શકું. હું કદી પણ નહિ આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.53 H and 15.83 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.73 H and 13.85 pF 0.53 H and 15.83 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.73 H and 13.85 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
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