MGVCL Exam Paper (30-07-2021 Shift 3) નીચે પૈકી 'ઓસોડ' નો સમાનર્થી શબ્દ કયો છે? વૃંદા ઔષધ અમર અનરવું વૃંદા ઔષધ અમર અનરવું ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Fill in the blanks with suitable Preposition from the given alternatives.BCCI receives____1000 applications for Team India head coach position over for against since over for against since ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In which of the following situations, there is no need to provide directional overcurrent protection. double end fed, single feeder single end fed, parallel feeder ring main single end fed, single feeder double end fed, single feeder single end fed, parallel feeder ring main single end fed, single feeder ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Directional overcurrent relay protection is used for parallel feeder and ring main system.It is not used for the protection of radial system.
MGVCL Exam Paper (30-07-2021 Shift 3) The complex power injections at a bus are shown in figure Two lines connected drawing the powers as shown in figure. The complex power in the line-2 "S2" is 2-j1 2-j5 2+j1 2+j5 2-j1 2-j5 2+j1 2+j5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Total power generate (Sg) = S1 + S2S2 = Sg - S1= 5 + 3j - 3 + 2j= 2 + 5j
MGVCL Exam Paper (30-07-2021 Shift 3) In a power network, 375 kV is recorded at a 400 kV bus. A 45 MVAR, 400 kV shunt reactor is connected to the bus. What is the reactive power absorbed by the shunt reactor? 39.55 MVAR 49.55 MVAR 59.55 MVAR 69.55 MVAR 39.55 MVAR 49.55 MVAR 59.55 MVAR 69.55 MVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Q = V²/XX = 400²/45= 3555.55 ohmFor 375 kV,Q = 375²/3555.55= 39.55 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
EXAMIANS