MGVCL Exam Paper (30-07-2021 Shift 3) નીચે પૈકી 'ઓસોડ' નો સમાનર્થી શબ્દ કયો છે? અમર અનરવું ઔષધ વૃંદા અમર અનરવું ઔષધ વૃંદા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Tiger Woods is associated with which of the following fields? Cinema Sports Literature Politics Cinema Sports Literature Politics ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Name the application under MS Office software bundle, that we use to create audio- visual presentation. MS Word MS Power point MS Excel MS Access MS Word MS Power point MS Excel MS Access ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Which country leads in the production of biofuel in the world? Brazil Germany Argentina United States of America Brazil Germany Argentina United States of America ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rank - Country - Production (thousands barrel)1 - US - 9402 - Brazil - 4493 - Germany - 684 - China - 68
MGVCL Exam Paper (30-07-2021 Shift 3) Arunachal Pradesh does not share its borders with which one of the following nations? Bhutan Myanmar China Bangladesh Bhutan Myanmar China Bangladesh ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The current flowing in to a balanced delta connected load through line 'a' is 10 A when the conductor of line ’b’ is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of ’abc’. Ia₀ = 10 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 10 A.Ia₁ = (-5 + j2.44) A.Ia₂ = (5 - j2.44) A. Ia₀ = 0 A.Ia₁ = (-5 + j2.88) A.Ia₂ = (5 - j2.88) A. Ia₀ = 0 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 10 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 10 A.Ia₁ = (-5 + j2.44) A.Ia₂ = (5 - j2.44) A. Ia₀ = 0 A.Ia₁ = (-5 + j2.88) A.Ia₂ = (5 - j2.88) A. Ia₀ = 0 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(10 + 10∟-120°)= 5 + j*2.88 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(10 + 10∟120°)= 5 - j*2.88 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
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