MGVCL Exam Paper (30-07-2021 Shift 3) Continuous and rapid variations in the load current magnitude which causes voltage variations is known as Harmonics Voltage sag Flicker Voltage distortion Harmonics Voltage sag Flicker Voltage distortion ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When voltage changes occur in rapid succession, with magnitudes large enough to cause lighting level variations.The human eye-brain response is most sensitive to periodic r.m.s. voltage changes that occur at around 8 - 10 cycles per second.
MGVCL Exam Paper (30-07-2021 Shift 3) દ્રશ્ય' શબ્દનો વિરુદ્ધાર્થ શબ્દ આપેલો વિકલ્પોમાંથી કયો છે? દ્રષ્ટિવંત દ્રષ્ટિ અદ્રશ્ય દ્રશ્યમાન દ્રષ્ટિવંત દ્રષ્ટિ અદ્રશ્ય દ્રશ્યમાન ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The sending end and receiving end voltages of the short transmission line are 150 kV and 120 kV respectively. Calculate its percentage voltage regulation. 30% 40% 20% 25% 30% 40% 20% 25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,Vs - sending end voltage in kVVr - Receiving end voltage in kV.Voltage regulation = (Vs - Vr)/Vr= (150 - 120)/120= 0.25% R = 25 %
MGVCL Exam Paper (30-07-2021 Shift 3) A 10-pole induction motor is supplied by a 6-pole alternator, which is driven at 1400 rpm. If the motor runs with a slip of 5%, what is its speed? 798 rpm 882 rpm 1425 rpm 1575 rpm 798 rpm 882 rpm 1425 rpm 1575 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Slip of the induction motor,S = (Ns - Nr)/NsNs = (120*f)/PPoles (P) = 61400 = (120*f)/6f = 70 HzFor P = 10Ns = (120*70)/10= 840 rpmNr = Ns(1 - S)= 840*(1 - 0.05)= 798 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) A star connected synchronous generator rated at 500 MVA, 50 kV has a reactance of 0.5 pu. Find the ohmic value of the reactance. 1 Ω 0.1 Ω 2.5 Ω 0.25 Ω 1 Ω 0.1 Ω 2.5 Ω 0.25 Ω ANSWER EXPLANATION DOWNLOAD EXAMIANS APP pu = actual/baserated phase consired at base value for alternator.ohmic pu = ohmic actual/ohmic basepu = ohmic actual*current base/voltage baseConsider all above phase valuesMVA (3phase) = 3 Vph IphIph = 500*10⁶/(3*28901.73) = 5766.66 Apu = ohmic actual*current base/voltage base0.5 = ohmic actual*5766.66/28901.73ohmic actual = 2.5 Ω
MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in First Generation Computers Fourth Generation Computers Third Generation Computers Second Generation Computers First Generation Computers Fourth Generation Computers Third Generation Computers Second Generation Computers ANSWER DOWNLOAD EXAMIANS APP
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