• HOME
  • QUIZ
  • CONTACT US
EXAMIANS
  • COMPUTER
  • CURRENT AFFAIRS
  • ENGINEERING
    • Chemical Engineering
    • Civil Engineering
    • Computer Engineering
    • Electrical Engineering
    • Mechanical Engineering
  • ENGLISH GRAMMAR
  • GK
  • GUJARATI MCQ

MGVCL Exam Paper (30-07-2021 Shift 3)

MGVCL Exam Paper (30-07-2021 Shift 3)
Tiger Woods is associated with which of the following fields?

Literature
Politics
Cinema
Sports

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
The elements are specialized computers used to connect two or more transmission lines.

Switching
Transfering
Broadcasting
Networking

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
A single phase full converter bridge, connected to 230 V, 50 Hz source is feeding a load R =10 Ω in series with a large inductance that makes the load current ripple free. For a firing angle of 450, calculate the rectification efficiency.

76.66%
28.33%
63.66%
50.55%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Rectification efficiency = DC output power/AC input power

MGVCL Exam Paper (30-07-2021 Shift 3)
A DC shunt generator has an induced voltage of 220 V on open circuit. When the machine is on load the terminal voltage is 200 V. Find the load current if the field resistance is 100 Ω and armature resistance is 0.2 Ω.

98 A
102 A
96 A
104 A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Voltage equation for Dc shunt generator,
Eb = V + Ia*Ra
V = Ish*Rsh
Ish = 200/100
= 2 A
Eb = V + Ia*Ra
20 = Ia*Ra
Ia = 20/0.2
= 100 A
I = 100 - 2
= 98 A

MGVCL Exam Paper (30-07-2021 Shift 3)
If a cable of homogeneous insulation has maximum stress of 6 kV/mm, then the dielectric strength of insulation should be ____

3 kV/mm
12 kV/mm
6 kv/mm
1.5 kV/mm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

If a cable have homogeneous insulation then the dielectric strength of insulation should be is equal to maximum dielectric strength.

MGVCL Exam Paper (30-07-2021 Shift 3)
A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 2 hours. What is the permissible overload for a duration of two hours. Assume the permissible load kVA as a fraction of rated kVA is 1.43.

1050 kVA
1430 kVA
700 kVA
715 kVA

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Permissible overload for transformer = Full load kVA*factor for permissible overload
= 1000*1.43
= 1430 kVA

MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 3)

DOWNLOAD APP

  • APPLE
    from app store
  • ANDROID
    from play store

SEARCH

LOGIN HERE


  • GOOGLE

FIND US

  • 1.70K
    FOLLOW US
  • EXAMIANSSTUDY FOR YOUR DREAMS.
  • SUPPORT :SUPPORT EMAIL ACCOUNT : examians@yahoo.com

OTHER WEBSITES

  • GUJARATI MCQ
  • ACCOUNTIANS

QUICK LINKS

  • HOME
  • QUIZ
  • PRIVACY POLICY
  • DISCLAIMER
  • TERMS & CONDITIONS
  • CONTACT US
↑