MGVCL Exam Paper (30-07-2021 Shift 3) સાબરમતી: અમદાવાદ:: મૂસી: ગોવા હૈદરાબાદ લંડન વેનિસ ગોવા હૈદરાબાદ લંડન વેનિસ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In which of the following situations, there is no need to provide directional overcurrent protection. ring main double end fed, single feeder single end fed, parallel feeder single end fed, single feeder ring main double end fed, single feeder single end fed, parallel feeder single end fed, single feeder ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Directional overcurrent relay protection is used for parallel feeder and ring main system.It is not used for the protection of radial system.
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.73 mH and 13.85 pF 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.53 mH and 15.83 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
MGVCL Exam Paper (30-07-2021 Shift 3) A conductor having surface density is embedded in a dielectric medium of permittivity. The electric field in the medium is E. If it is known that the pressure p on the conductor surface is equal to the electric energy density in the medium, then p (in SI unit)is given by σ/(4πε) σ²/(2πε) σ²/(4π) σ²/(2ε) σ/(4πε) σ²/(2πε) σ²/(4π) σ²/(2ε) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP As the point is near to the conductor will act as infinite sheetElectric field (E) is given by:E = σ²/(2ϵ)
MGVCL Exam Paper (30-07-2021 Shift 3) The complex power injections at a bus are shown in figure Two lines connected drawing the powers as shown in figure. The complex power in the line-2 "S2" is 2+j5 2-j1 2+j1 2-j5 2+j5 2-j1 2+j1 2-j5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Total power generate (Sg) = S1 + S2S2 = Sg - S1= 5 + 3j - 3 + 2j= 2 + 5j
MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in Third Generation Computers Fourth Generation Computers First Generation Computers Second Generation Computers Third Generation Computers Fourth Generation Computers First Generation Computers Second Generation Computers ANSWER DOWNLOAD EXAMIANS APP