MGVCL Exam Paper (30-07-2021 Shift 3) સાબરમતી: અમદાવાદ:: મૂસી: વેનિસ લંડન હૈદરાબાદ ગોવા વેનિસ લંડન હૈદરાબાદ ગોવા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Replace the braketed phrase grammatically and conceptually with the help of the given opation. If the given sentence is correct then select the option ’The given sentence is correct’.The corono virus continued to spread, with the development of infections advancing quickly continued to spreading, with the development of infections The given sentence is correct continued for spread, with the development of infections continue to spread, with the development of infections continued to spreading, with the development of infections The given sentence is correct continued for spread, with the development of infections continue to spread, with the development of infections ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Fill in the blanks with suitable Preposition from the given alternatives.BCCI receives____1000 applications for Team India head coach position over since for against over since for against ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) 1. મોટેભાગે 'જાણે' શબ્દ હોય ત્યારે,ઉત્પ્રેક્ષા અલંકાર બને છે.૨. જયારે ઉપમેય અને ઉપમાન એક જ હોય ત્યારે ઉપમા અલંકાર બને છે.સરખાવવામાં આવેલ બે શબ્દોની વચ્ચે 'જયારે', 'જેવો', 'જેવી' જેવા શબ્દો આવે ત્યારે રૂપક અલંકાર બને.જયારે ટીકા કે નિંદા કે વ્યંગના રૂપે પ્રશંસા કરાય ત્યારે અતિશયોક્તિ અલંકાર બને.ઉપરોક્ત વિધાનોમાંથી કયું/ક્યાં વિધાનો સાચા છે. માત્ર 4 2, 4 1, 3 માત્ર 1 માત્ર 4 2, 4 1, 3 માત્ર 1 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Choose the word which expresses nearly the opposite meaning of the given word "DILIGENT " Busy Active Careful Lasy Busy Active Careful Lasy ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 20 Ω and the resistance of the resistor connected to the sound core was 40 Ω. Calculate the distance of the fault point from the test end. 400 m 300 m 100 m 200 m 400 m 300 m 100 m 200 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (20/60)*600= 200 m.