MGVCL Exam Paper (30-07-2021 Shift 3) Data Encryption Standard (DES) was designed by Apple None of these IBM Microsoft Apple None of these IBM Microsoft ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In a power network, 375 kV is recorded at a 400 kV bus. A 45 MVAR, 400 kV shunt reactor is connected to the bus. What is the reactive power absorbed by the shunt reactor? 69.55 MVAR 39.55 MVAR 49.55 MVAR 59.55 MVAR 69.55 MVAR 39.55 MVAR 49.55 MVAR 59.55 MVAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Q = V²/XX = 400²/45= 3555.55 ohmFor 375 kV,Q = 375²/3555.55= 39.55 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) The threshold voltage of an N-channel enhancement mode MOSFET is 0.5 V. When the device is biased at a gate voltage of 3 V, pinch-off would occur at a drain voltage of 1.5 V 3.5 V 2.5 V 4.5 V 1.5 V 3.5 V 2.5 V 4.5 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Vds = Vgs - VtVds = 3 - 0.5Vds = 2.5 V
MGVCL Exam Paper (30-07-2021 Shift 3) What is the full form of the acronym 'SWIFT', in financial institution? Society website in Financial Terms Social Wide in Financial Transaction Social World interconnection in Financial Tech process Society for Worldwide Interbank Financial Telecommunication Society website in Financial Terms Social Wide in Financial Transaction Social World interconnection in Financial Tech process Society for Worldwide Interbank Financial Telecommunication ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The maximum value of power factor is ____ and it exists in a pure____ circuit. 0.866, resistive 1, inductive 1, resistive 0.866, inductive 0.866, resistive 1, inductive 1, resistive 0.866, inductive ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Value of power factor is varies from 0 to 1.R→PF = 1L→PF = 0 lagC→PF = 0 leadR-L→0 lag < PF < 1R-C→0 lead < PF < 1R-C-L→depends on value of R, L and C. PF = R/Z
MGVCL Exam Paper (30-07-2021 Shift 3) The current in the coil of a large electromagnet falls from 6 A to 2 A in 10 ms. The induced emf across the coil is 100 V. Find the self-inductance of the coil. 1.25 H 0.75 H 0.25 H 0.5 H 1.25 H 0.75 H 0.25 H 0.5 H ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation of self inductance:V = Ls*(di/dt)Ls = V/(di/dt)= 100/((6 - 2)/(0.01))= 0.250 H= 250 mH
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