MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in Third Generation Computers Second Generation Computers Fourth Generation Computers First Generation Computers Third Generation Computers Second Generation Computers Fourth Generation Computers First Generation Computers ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C? 0.73 H and 13.85 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.53 H and 15.83 pF 0.73 H and 13.85 pF 0.53 mH and 15.83 pF 0.73 mH and 13.85 pF 0.53 H and 15.83 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Vc = I*Xc460 = 2*(1/(2*ᴨ*50*C))C = 2/(460*2*50*ᴨ)= 1.385*10⁻⁵ F= 13.85 FV_L = I*X_LL = V/(I*2*ᴨ*f)= 460/(2*ᴨ*50*2)= 0.7345 H
MGVCL Exam Paper (30-07-2021 Shift 3) When was the Constitution of India adopted by the Constituent Assembly? January 25 1930 13th January 1950 15th August 1947 26th November 1949 January 25 1930 13th January 1950 15th August 1947 26th November 1949 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The maximum value of power factor is ____ and it exists in a pure____ circuit. 1, inductive 0.866, inductive 1, resistive 0.866, resistive 1, inductive 0.866, inductive 1, resistive 0.866, resistive ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Value of power factor is varies from 0 to 1.R→PF = 1L→PF = 0 lagC→PF = 0 leadR-L→0 lag < PF < 1R-C→0 lead < PF < 1R-C-L→depends on value of R, L and C. PF = R/Z
MGVCL Exam Paper (30-07-2021 Shift 3) Which country leads in the production of biofuel in the world? United States of America Germany Argentina Brazil United States of America Germany Argentina Brazil ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rank - Country - Production (thousands barrel)1 - US - 9402 - Brazil - 4493 - Germany - 684 - China - 68
MGVCL Exam Paper (30-07-2021 Shift 3) The current flowing in to a balanced delta connected load through line 'a' is 10 A when the conductor of line ’b’ is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of ’abc’. Ia₀ = 10 A.Ia₁ = (-5 + j2.44) A.Ia₂ = (5 - j2.44) A. Ia₀ = 0 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 10 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 0 A.Ia₁ = (-5 + j2.88) A.Ia₂ = (5 - j2.88) A. Ia₀ = 10 A.Ia₁ = (-5 + j2.44) A.Ia₂ = (5 - j2.44) A. Ia₀ = 0 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 10 A.Ia₁ = (-1.66 + j2.88) A.Ia₂ = (1.66 + j2.88) A. Ia₀ = 0 A.Ia₁ = (-5 + j2.88) A.Ia₂ = (5 - j2.88) A. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(10 + 10∟-120°)= 5 + j*2.88 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(10 + 10∟120°)= 5 - j*2.88 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
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