MGVCL Exam Paper (30-07-2021 Shift 3) Transistors were used in First Generation Computers Third Generation Computers Second Generation Computers Fourth Generation Computers First Generation Computers Third Generation Computers Second Generation Computers Fourth Generation Computers ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) As per Stockholm International Peace Research Institute (SIPRI) report 2019 for the period 2014-2018, which country is the largest arms importer in the world? India Germany Saudi Arabia Myanmar India Germany Saudi Arabia Myanmar ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The magnetizing inrush current in a transformer is rich in the harmonic component. fifth third seventh second fifth third seventh second ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2nd harmonics contains - 60 to 55 %3rd harmonics contains - 40 - 50%
MGVCL Exam Paper (30-07-2021 Shift 3) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 400 W and -50 W. Calculate the reactive power taken by the load 450/√3 VAR 450√3 VAR 350/√3 VAR 350√3 VAR 450/√3 VAR 450√3 VAR 350/√3 VAR 350√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken (Q) = √3*(W1 - W2)= √3*(450 + 50)= √3*450 kVAR
MGVCL Exam Paper (30-07-2021 Shift 3) If the phase velocity of a plane wave in a perfect dielectric is 0.4 times its value in free space, then what is the relative permittivity of the dielectric? 4.25 6.25 1.25 2.5 4.25 6.25 1.25 2.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The equation is given by:Vp (Phase velocity) = (Velocity of light in free space/Phase velocity)²= (1/0.4)²= 6.25
MGVCL Exam Paper (30-07-2021 Shift 3) The current in the coil of a large electromagnet falls from 6 A to 2 A in 10 ms. The induced emf across the coil is 100 V. Find the self-inductance of the coil. 0.75 H 0.5 H 0.25 H 1.25 H 0.75 H 0.5 H 0.25 H 1.25 H ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation of self inductance:V = Ls*(di/dt)Ls = V/(di/dt)= 100/((6 - 2)/(0.01))= 0.250 H= 250 mH