A 3 pF capacitor is charged by a constant current of 2 pA for six seconds. The voltage across the capacitor at the end of charging will be

• A. 4 V
• B. 6 V
• C. 8 V
• D. 2 V

Answer: (A)

Equation know that the charge stored in a capacitor is given as:
Q = C*V
Q = I*t
V = (I*t)/C
= (2μ*6)/(3μ)
= 4 V