MGVCL Exam Paper (30-07-2021 Shift 3) સારું:નરસું::શુક્લ: ? અમર અવિશાની કૃષ્ણ પરમ અમર અવિશાની કૃષ્ણ પરમ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The most commonly used method for the protection of three phase feeder is Time graded protection Reverse power protection Differential protection None of these Time graded protection Reverse power protection Differential protection None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Differential Pilot Wire Protection is simply a differential protection scheme applied to feeders.Several differential schemes are applied for protection of line but Mess Price Voltage balance system and Translay Scheme are most popularly used.
MGVCL Exam Paper (30-07-2021 Shift 3) A star connected synchronous generator rated at 500 MVA, 50 kV has a reactance of 0.5 pu. Find the ohmic value of the reactance. 1 Ω 2.5 Ω 0.25 Ω 0.1 Ω 1 Ω 2.5 Ω 0.25 Ω 0.1 Ω ANSWER EXPLANATION DOWNLOAD EXAMIANS APP pu = actual/baserated phase consired at base value for alternator.ohmic pu = ohmic actual/ohmic basepu = ohmic actual*current base/voltage baseConsider all above phase valuesMVA (3phase) = 3 Vph IphIph = 500*10⁶/(3*28901.73) = 5766.66 Apu = ohmic actual*current base/voltage base0.5 = ohmic actual*5766.66/28901.73ohmic actual = 2.5 Ω
MGVCL Exam Paper (30-07-2021 Shift 3) Choose the best option from the given alternatives which can be substituted for the given word/sentence.Code of diplomatic etiquette and precedence Wardrobe Protocol Sheath Secular Wardrobe Protocol Sheath Secular ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) When was the Constitution of India adopted by the Constituent Assembly? January 25 1930 13th January 1950 15th August 1947 26th November 1949 January 25 1930 13th January 1950 15th August 1947 26th November 1949 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 20 Ω and the resistance of the resistor connected to the sound core was 40 Ω. Calculate the distance of the fault point from the test end. 100 m 400 m 300 m 200 m 100 m 400 m 300 m 200 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (20/60)*600= 200 m.
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