MGVCL Exam Paper (30-07-2021 Shift 3) હું અહી આવી શકું' વાક્યને સ્થળવાચક ક્રીયાવીશેષણમાં ફેરવો. હું કદી પણ નહિ આવી શકું. હું નિયમિત રીતે અહી આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. હું આજે નહિ આવી શકું. હું કદી પણ નહિ આવી શકું. હું નિયમિત રીતે અહી આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. હું આજે નહિ આવી શકું. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Find the word which is correctly spelt from the given options. Seriuous Abolishid Syndrome Obecity Seriuous Abolishid Syndrome Obecity ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.4 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.8 Hz 1.6 Hz 1.2 Hz 0.8 Hz 1.8 Hz 1.6 Hz 1.2 Hz 0.8 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (1.1/0.6)*cosδ= (1.1/0.6)*0.5= 0.91M = (H*s)/(πf)= 4/(50π)fn = (0..91/(4/50π))= 8.9 rad/sec= 1.2 Hz
MGVCL Exam Paper (30-07-2021 Shift 3) મેં મીઠાઈ બનાવી'. વાક્યને કેવળ ક્રિયાપદની પ્રેરક રચના કઈ છે? હું મીઠાઈ બનાવવા લાગી. મેં મીઠાઈ બનાવડાવી. મીઠાઈ તો હું જ બનવું ને! મેં મીઠાઈ બનાવી લીધી. હું મીઠાઈ બનાવવા લાગી. મેં મીઠાઈ બનાવડાવી. મીઠાઈ તો હું જ બનવું ને! મેં મીઠાઈ બનાવી લીધી. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Choose the best option from the given alternatives which can be substituted for the given word/sentence.Code of diplomatic etiquette and precedence Sheath Protocol Wardrobe Secular Sheath Protocol Wardrobe Secular ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 20 Ω and the resistance of the resistor connected to the sound core was 40 Ω. Calculate the distance of the fault point from the test end. 200 m 300 m 400 m 100 m 200 m 300 m 400 m 100 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (20/60)*600= 200 m.
EXAMIANS